Equations that are always true
An equation like 2x + 3 = 11 is true only when x = 4. An algebraic identity is true for every value:
(a + b)² = a² + 2ab + b²
Try a = 3, b = 4: (7)² = 49 and 9 + 24 + 16 = 49 ✓. It works for any numbers.
The key identities
| Identity | Name |
|---|---|
| (a + b)² = a² + 2ab + b² | square of a sum |
| (a − b)² = a² − 2ab + b² | square of a difference |
| (a + b)(a − b) = a² − b² | difference of squares |
| (a + b)³ = a³ + 3a²b + 3ab² + b³ | cube of a sum |
| a³ + b³ = (a + b)(a² − ab + b²) | sum of cubes |
| a³ − b³ = (a − b)(a² + ab + b²) | difference of cubes |
The first two give perfect square trinomials.
Why (a + b)² isn’t a² + b²
Picture a square with side (a + b). It splits into:
| a | b | |
|---|---|---|
| a | a² | ab |
| b | ab | b² |
The total is a² + 2ab + b². The two "ab" rectangles are what people forget.
Using identities to expand
To expand a binomial squared, use the pattern.
- (x + 5)² = x² + 10x + 25
- (2y − 3)² = 4y² − 12y + 9
- (m + 7)(m − 7) = m² − 49
Using identities to factor
To factor, recognize the pattern in reverse.
- x² − 36 = (x + 6)(x − 6)
- 9a² − 25 = (3a + 5)(3a − 5)
- x² + 14x + 49 = (x + 7)²
- 4p² − 20p + 25 = (2p − 5)²
Test for a perfect square trinomial: first and last terms are perfect squares, and the middle term is twice the product of their roots.
Mental maths tricks
- 51² = (50 + 1)² = 2,500 + 100 + 1 = 2,601
- 49 × 51 = (50 − 1)(50 + 1) = 2,500 − 1 = 2,499
- 98² = (100 − 2)² = 10,000 − 400 + 4 = 9,604
Identity vs equation
| Equation | Identity |
|---|---|
| true for some values | true for all values |
| 3x = 12 | 3(x + 4) = 3x + 12 |
| solve it | prove or use it |
Worked examples
Example 1: Expand (3x + 2)² → 9x² + 12x + 4.
Example 2: Factor 16 − y² → (4 + y)(4 − y).
Example 3: Is x² + 6x + 8 a perfect square? Last term 8 isn’t a square → no.
Common mistakes
- (a + b)² = a² + b² (forgetting 2ab).
- Sign errors: (a − b)² has −2ab but +b².
- Trying to factor a sum of squares like x² + 9 with real numbers. It doesn’t factor.
Try it yourself
- Expand (x − 4)².
- Expand (5a + b)(5a − b).
- Factor x² − 81.
- Factor 25x² + 30x + 9.
- Use an identity to calculate 103².
Answers: 1) x² − 8x + 16 2) 25a² − b² 3) (x + 9)(x − 9) 4) (5x + 3)² 5) 10,609
Quick recap
- An algebraic identity is true for all values.
- Key identities: (a ± b)² and the difference of squares.
- Use them to expand, factor and calculate mentally.