The bell curve
Many natural measurements (heights, test scores, measurement errors) form a normal distribution: a symmetric, bell curve centred on the mean μ.
Features:
- Mean = median = mode, at the centre.
- Symmetric about the mean.
- Tails approach (but never reach) the axis.
- Shape set by μ (centre) and σ (spread).
The empirical rule (68–95–99.7)
| Range | Approximate % of data |
|---|---|
| μ ± 1σ | 68% |
| μ ± 2σ | 95% |
| μ ± 3σ | 99.7% |
Example: Adult heights: μ = 170 cm, σ = 8 cm.
- 68% between 162 and 178 cm
- 95% between 154 and 186 cm
- 99.7% between 146 and 194 cm
Because of symmetry: 34% between μ and μ + σ; 13.5% between μ + σ and μ + 2σ; 2.5% above μ + 2σ.
z-scores
A z-score measures how many standard deviations a value is from the mean:
z = (x − μ) / σ
Example: A 186 cm person: z = (186 − 170)/8 = 2.
z-scores let you compare values from different distributions.
Example: 82 on a test (μ = 70, σ = 6): z = 2. 90 on another (μ = 80, σ = 10): z = 1. The first is relatively better.
The standard normal distribution
Converting to z-scores gives the standard normal distribution (μ = 0, σ = 1). Tables or technology give the area under the curve (the proportion of data) to the left of any z.
| z | Area to the left |
|---|---|
| −2 | 0.0228 |
| −1 | 0.1587 |
| 0 | 0.5000 |
| 1 | 0.8413 |
| 1.5 | 0.9332 |
| 2 | 0.9772 |
Finding proportions
Example: What percent of adults are taller than 182 cm?
- z = (182 − 170)/8 = 1.5
- Area left of 1.5 = 0.9332
- Above: 1 − 0.9332 = 6.7%
Between two values: P(162 < x < 182) = P(−1 < z < 1.5) = 0.9332 − 0.1587 = 77.5%.
Working backwards
Example: What height is the 90th percentile?
- z for 0.90 ≈ 1.28
- x = μ + zσ = 170 + 1.28(8) ≈ 180.2 cm
Technology
Spreadsheets: =NORM.DIST(x, μ, σ, TRUE) gives the area to the left; =NORM.INV(p, μ, σ) gives the value. Calculators have normalcdf and invNorm.
Is my data normal?
Check that a histogram is roughly bell-shaped and symmetric, with no strong skew. Not all data is normal (incomes are usually right-skewed).
Worked examples
Example 1: μ = 50, σ = 5. What percent lies between 45 and 55? 68%.
Example 2: z-score of 38 when μ = 50, σ = 4? −3.
Example 3: Percent below z = −1? 15.9%.
Common mistakes
- Forgetting that the area is a proportion (multiply by 100 for percent).
- Using the left-area when you need the right-area.
- Assuming all data is normal.
Try it yourself
- μ = 100, σ = 15. What range contains about 95% of values?
- z-score of 130 in that distribution?
- Percent of values above z = 2?
- Value at z = −1.5 when μ = 60, σ = 4?
Answers: 1) 70 to 130 2) 2 3) about 2.3% (2.5% by the empirical rule) 4) 54
Quick recap
- The normal distribution is a symmetric bell curve.
- Empirical rule: 68–95–99.7.
- z-scores and the standard normal distribution give the area under the curve.