Multiply the choices
The fundamental counting principle: if one choice can be made in m ways and a second in n ways, the two together can be made in m × n ways.
It extends to any number of stages: m × n × p × …
Example: outfits
3 shirts, 4 pants and 2 pairs of shoes:
3 × 4 × 2 = 24 outfits
Example: meals
A restaurant offers 4 appetizers, 6 mains and 3 desserts. Number of 3-course meals:
4 × 6 × 3 = 72
Repetition allowed vs not
With repetition (items can be reused):
- 4-digit PIN using 0–9: 10 × 10 × 10 × 10 = 10,000
Without repetition (each item used once):
- 4-digit PIN with no repeated digits: 10 × 9 × 8 × 7 = 5,040
Licence plates
Ontario passenger plates have 4 letters and 3 digits (ABCD 123):
26⁴ × 10³ = 456,976 × 1,000 = 456,976,000 possible plates (before removing restricted combinations).
Restrictions
Handle the restricted stage first.
Example: How many 3-digit numbers (100–999) are odd?
- Hundreds digit: 1–9 → 9 choices
- Tens digit: 0–9 → 10
- Ones digit: 1, 3, 5, 7, 9 → 5
- Total: 9 × 10 × 5 = 450
Example: How many 3-letter codes from A–Z start with a vowel and have no repeats?
- 1st: 5 vowels; 2nd: 25; 3rd: 24 → 5 × 25 × 24 = 3,000
"Or" situations: add
If choices are separate cases (not stages), add.
Example: You can take the bus (3 routes) or the train (2 routes). Ways to travel: 3 + 2 = 5.
Connection to probability
P(guessing a 4-digit PIN in one try) = 1/10,000.
Worked examples
Example 1: Flip a coin, roll a die, spin a 4-colour spinner. Outcomes? 2 × 6 × 4 = 48.
Example 2: Passwords: 2 letters then 3 digits, repetition allowed. 26² × 10³ = 676,000.
Example 3: 5 runners. How many ways for 1st, 2nd, 3rd? 5 × 4 × 3 = 60.
Common mistakes
- Adding when you should multiply (stages in sequence multiply).
- Ignoring restrictions like "no leading zero".
- Forgetting to reduce choices when repetition isn’t allowed.
Try it yourself
- 5 flavours of ice cream and 3 types of cone. Combinations?
- 3-digit codes from 0–9, repetition allowed?
- Same, no repetition?
- How many even 4-digit numbers (1000–9999)?
- 8 students; how many ways to choose a president and vice-president?
Answers: 1) 15 2) 1,000 3) 720 4) 4,500 5) 56
Quick recap
- Fundamental counting principle: multiply the choices at each stage.
- Watch for repetition and restrictions.
- Add separate "or" cases.