Working backwards
Differentiation finds a rate from a function. Integration goes the other way: from a rate back to the function.
An antiderivative of f(x) is a function F(x) with F′(x) = f(x).
Example: An antiderivative of 2x is x², because d/dx x² = 2x.
The constant of integration
x², x² + 5 and x² − 17 all have derivative 2x. So the general antiderivative is:
x² + C
C is the constant of integration.
Notation: the indefinite integral
∫ f(x) dx = F(x) + C
- ∫ is the integral sign
- f(x) is the integrand
- dx shows the variable
This is called an indefinite integral.
Basic rules
| Function | Antiderivative |
|---|---|
| k (constant) | kx + C |
| xⁿ (n ≠ −1) | xⁿ⁺¹/(n + 1) + C (power rule for integration) |
| 1/x | ln|x| + C |
| eˣ | eˣ + C |
| e^(kx) | (1/k)e^(kx) + C |
| sin x | −cos x + C |
| cos x | sin x + C |
Constant multiple and sum rules work as for derivatives.
Examples
- ∫ x⁴ dx = x⁵/5 + C
- ∫ (6x² − 4x + 3) dx = 2x³ − 2x² + 3x + C
- ∫ √x dx = ∫ x^(1/2) dx = (2/3)x^(3/2) + C
- ∫ 1/x³ dx = ∫ x⁻³ dx = −1/(2x²) + C
- ∫ 5eˣ dx = 5eˣ + C
Check: differentiate your answer; you should get the integrand.
Initial conditions
An initial condition pins down C.
Example: f′(x) = 3x² + 2, f(1) = 5. Find f(x).
- f(x) = x³ + 2x + C
- 5 = 1 + 2 + C → C = 2
- f(x) = x³ + 2x + 2
Motion
- Position = ∫ velocity
- Velocity = ∫ acceleration
Example: a(t) = −9.8, v(0) = 15, s(0) = 2
- v(t) = −9.8t + 15
- s(t) = −4.9t² + 15t + 2
Worked examples
Example 1: ∫ 7 dx = 7x + C.
Example 2: ∫ (x³ + x) dx = x⁴/4 + x²/2 + C.
Example 3: ∫ cos x dx = sin x + C.
Common mistakes
- Forgetting + C.
- Power rule errors: add 1 to the exponent, then divide by the new exponent.
- Using the power rule for x⁻¹ (it gives ln|x|).
Try it yourself
- ∫ 4x³ dx
- ∫ (2x − 5) dx
- ∫ x^(−2) dx
- ∫ 3e^(2x) dx
- f′(x) = 6x, f(0) = 4. Find f(x).
Answers: 1) x⁴ + C 2) x² − 5x + C 3) −1/x + C 4) (3/2)e^(2x) + C 5) 3x² + 4
Quick recap
- An antiderivative reverses differentiation; integration finds it.
- Always add the constant of integration C in an indefinite integral.
- Use the power rule for integration and initial conditions to find specific functions.