Learn Index · Trigonometry Grade 11–12

Trigonometric equations

Solving for the angles that make a trigonometric statement true.

Read

Equations with many answers

A trigonometric equation is true only for certain angles. Because trig functions repeat, there are usually several solutions in one cycle, and infinitely many overall.

Basic strategy

  1. Isolate the trig function.
  2. Find the reference angle using the inverse trigonometric function (use the positive value).
  3. Use the CAST rule to find which quadrants give the correct sign.
  4. Write all solutions in the required interval.

Example 1

Solve 2 sin θ − 1 = 0 for 0° ≤ θ < 360°.

  • sin θ = ½
  • Reference angle: 30°
  • Sine is positive in I and II → θ = 30°, 150°

Example 2

Solve cos θ = −0.4 for 0° ≤ θ < 360°.

  • Reference angle: cos⁻¹(0.4) ≈ 66.4°
  • Cosine is negative in II and III
  • θ ≈ 180 − 66.4 = 113.6° and 180 + 66.4 = 246.4°

Example 3: tangent

Solve tan θ = √3 for 0 ≤ θ < 2π.

  • Reference angle π/3; tan positive in I and III
  • θ = π/3, 4π/3

Quadratic trig equations

Factor like a quadratic.

Example: 2 sin²θ − sin θ − 1 = 0

  • (2 sin θ + 1)(sin θ − 1) = 0
  • sin θ = −½ → θ = 210°, 330°
  • sin θ = 1 → θ = 90°
  • Solutions: 90°, 210°, 330°

Using identities

Example: 2cos²θ + 3 sin θ = 3

  • Replace cos²θ = 1 − sin²θ: 2 − 2sin²θ + 3 sin θ = 3
  • 2sin²θ − 3 sin θ + 1 = 0 → (2 sin θ − 1)(sin θ − 1) = 0
  • sin θ = ½ or 1 → 30°, 90°, 150°

Multiple angles

Example: sin 2θ = ½ for 0° ≤ θ < 360°

  • 2θ ranges over 0° to 720°
  • 2θ = 30°, 150°, 390°, 510°
  • θ = 15°, 75°, 195°, 255°

General solutions

The general solution lists all solutions:

sin θ = ½ → θ = 30° + 360°k or θ = 150° + 360°k, k an integer.

Worked examples

Example 1: cos θ = 1, 0° ≤ θ < 360° → 0°.

Example 2: 3 tan θ + 3 = 0 → tan θ = −1 → 135°, 315°.

Example 3: sin θ = 2? No solution (sine is between −1 and 1).

Common mistakes

  • Giving only the calculator’s answer and missing the second solution.
  • Using a negative value to find the reference angle.
  • Dividing by sin θ or cos θ, which can lose solutions. Factor instead.

Try it yourself

  1. sin θ = √2/2, 0° ≤ θ < 360°
  2. 2 cos θ + 1 = 0, 0° ≤ θ < 360°
  3. tan θ = 0.75, 0° ≤ θ < 360° (one decimal)
  4. cos²θ = ¼, 0° ≤ θ < 360°
  5. sin θ cos θ = 0, 0° ≤ θ < 360°

Answers: 1) 45°, 135° 2) 120°, 240° 3) 36.9°, 216.9° 4) 60°, 120°, 240°, 300° 5) 0°, 90°, 180°, 270°

Quick recap

  • Isolate, find the reference angle, then use CAST for all quadrants.
  • Factor quadratic equations; use identities to get one function.
  • State all solutions in the interval, or write a general solution.